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light of wavelength 4000 angstorms fall on a surface of cs calculate the energy of photoelectron emitted if critical wavelength for photoelectric effect in cs is 6600angstroms
energy released = h(f1-f2){here hf2=threshold frequency}
by calculating we get
f1=7.5*10^13
f2=4.5*1013
so E=7.95*10-21
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