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In a reaction,A+2B-------->2C,2 moles of A 3 mole of B and 2 mole of C are placed in a 2 L flask and the equilibrium concentration of C is 0.5 mol/L.The equilibrium constant K for the reaction is ans.-0.05 please tell how?

In a reaction,A+2B-------->2C,2 moles of A 3 mole of B and 2 mole of C are placed in a 2 L flask and the equilibrium concentration of C is 0.5 mol/L.The equilibrium constant K for the reaction is


ans.-0.05


please tell how?

Grade:12

2 Answers

Vikas TU
14149 Points
8 years ago

                                                  A          +          2B        -------->             2C 

Let t = 0 (Initially)                2                         3                                        2

       t = t                                  2 - x                    3 - 2x                               2x + 2 (Initially it was 2)

 

                                                Now, [C] = 0.5 mol/L = (2x + 2)/2 mol/L

                                                                                   x  = - 0.5

                                                Put x = - 0.5  at time t

                                               Thus, A = 2.5

                                                        B = 4

                                                        C = 1

                                           K = (C)2 / (A) (B)2

                                           K = (1/2)2/ (2.5/2) . (4/2)2  

               [Dividing moles by 2 {volume given} as we express here in   terms of concentration]

                                           K = 1/20

                                           K = 0.05

 

 

Approve plz!

 

 

  

 


Rishi Sharma
askIITians Faculty 646 Points
10 months ago
Dear Student,
Please find below the solution to your problem.

A + 2B → 2C
Let t = 0 (Initially) 2 3 2
t = t 2 - x 3 - 2x 2x + 2
x = -0.5
(Initially Now, [C] = 0.5 mol/L
= (2x + 2)/2 mol/L
Put x = - 0.5 at time t
Thus, A = 2.5
B = 4
C = 1
K=(C)^2/(A)(B)^2
K=(1/2)2/(2.5/2).(4/2)2
[Dividing moles by 2 {volume given} as we express here in terms of concentration
K = 1/20
K = 0.05

Thanks and Regards

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