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[OH(-)] = 10^(-4)2.[OH(-)] = 2*10^(-4)Ba(OH)2 <=> Ba(2+) + 2.OH(-)Ksp=10^-9so,[Ba(2+)].(2.10^-4)^2 = 10^-9[Ba(2+)] = 0.25 * 10^-1 (Ans)Please Approve. . .Thank You
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