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The correct order of equivalent conductance at infinite dilution of LiCl,NaCl,KCl?

The correct order of equivalent conductance at infinite dilution of LiCl,NaCl,KCl?

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10 Answers

BOBBY VEERRAJU
14 Points
9 years ago

KCl>NaCl>LiCl

ajay ammA
29 Points
9 years ago

KCl>NaCl>LiCl this is the correct answer because of KCl is stronger electrolyte than NaCl which is stronger than LiCl.

heena heena
16 Points
9 years ago

Kcl > NaCl > LiCl this is the correct answer because of KCl is stronger electrolyte than NaCl which is stronger than LiCl?

mounika
8 Points
8 years ago
NaCl>KCl>LiCl.BECAUSE NACL STRONGER ELECTROLYTETHAN KCl
VEERU YERRAYYA
45 Points
8 years ago
The lattice energy of NaCl is -787.5 kJ/mol. The lattice energy of KCl is -715 kJ/mol. so that NaCl > KCl > LiCl
Saswat David
31 Points
8 years ago
It will be Li>Na>K Smaller the size, more the equivalent ionic conductance. All the above answers are shit.
pogula sumanth
35 Points
7 years ago
KCl>NaCl>LiCl
Drake
277 Points
7 years ago
 That is only one force, the K+ ion is larger than the Na+ ion, so the distance between the K+ and Cl- ions is greater than between Na+ and Cl-, decreasing the bond strength. Yes, KCl has a high bond energy, but not as high as NaCl. 
Hence KCl>NaCl>LiCl
 
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Nitesh
11 Points
4 years ago
Since in aqueous. Phase size order is li+> Na+>k+. So ionic mobility of li+ is least and so conductance is less so right order is k+>Na+>li+
Rishi Sharma
askIITians Faculty 646 Points
2 years ago
Dear Student,
Please find below the solution to your problem.

That is only one force, the K+ ion is larger than the Na+ ion, so the distance between the K+ and Cl- ions is greater than between Na+ and Cl-, decreasing the bond strength. Yes, KCl has a high bond energy, but not as high as NaCl.
Hence KCl>NaCl>LiCl

Thanks and Regards

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