1.find the number of a quanta of radiation of frequency 4.67*1013s-1 that must be absorabed in order to melt 5gm of ice. energy required to melt 1gm of ice is 333j?2.calculate the velocity of electrostatic potential energy of to electrons separated by 3.0 in vacuum. express your answers in jouls and electron volt?3.energy required to stop the ejection of electrons is 0.24 eV. calculate the work function when radiationsof ?=253.7 nm strikes the plate?
vrashank joshi , 12 Years ago
Grade
1 Answers
Pankaj
Last Activity: 10 Years ago
Using We can calculate the energy of one photon using E = hv Given that v = 4.67×1013s-1 h = 6.62 ×10−34 J.S We get, E = (6.62 ×10−34)( 4.67×1013s-1 ) = 30.94 × 10-21 J Number of quanta required to melt five gram of ice = 1665/30.94 × 10-21 = 53.81 × 1021
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