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24.5 gm of kclo3 heated to give o2 which on reaction with h2 horms h2o. this h2 comes from zinc and h2so4 reaction. the amount of zinc required is?

7 years ago

Answers : (2)

Guru Prasad Singh
18 Points
							

The given reactions are as follows:

2KClO3------> 2KCl+3O2

2H2+O2----> 2H2O

Zn+H2SO4-----> ZnSO4+H2

 

Now, 122.5 of KClO3 gives 96 g of O2

Therefore O2 obtained from 24.5 gm of KClO3= 96/122.5*24.5= 19.2 gm of O2

Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.

Therefore Mass of H2 reacting with 19.2 gm of O2=4/32*19.2= 2.4gm

Now, 64 gm of Zn gives 2 gm of H2 gas.

Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*2.4=76.8 gm

Hence Amount of Zinc required for the given condition of reaction is 76.8gm.

Hope it Helps you!!!

7 years ago
Rakesh Chandra Kalita
19 Points
							The given reactions are as follows:2KClO3------> 2KCl+3O22H2+O2----> 2H2OZn+H2SO4-----> ZnSO4+H2 Now, 245 of KClO3 gives 96 g of O2Therefore O2 obtained from 24.5 gm of KClO3= 96/245*24.5= 9.6 gm of O2Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.Therefore Mass of H2 reacting with 9.6 gm of O2=4/32*9.6= 1.2gmNow, 64 gm of Zn gives 2 gm of H2 gas.Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*1.2=39 gmHence Amount of Zinc required for the given condition of reaction is 39 gm.
						
2 years ago
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