24.5 gm of kclo3 heated to give o2 which on reaction with h2 horms h2o. this h2 comes from zinc and h2so4 reaction. the amount of zinc required is?

The given reactions are as follows:

2KClO₃------> 2KCl+3O₂

2H₂+O₂----> 2H₂O

Zn+H₂SO₄-----> ZnSO₄+H₂

 

Now, 122.5 of KClO₃ gives 96 g of O₂

Therefore O₂ obtained from 24.5 gm of KClO₃= 96/122.5*24.5= 19.2 gm of O₂

Now 32 gm of O₂ react with 4gm of H₂ to give 36 gm of H₂O.

Therefore Mass of H₂ reacting with 19.2 gm of O₂=4/32*19.2= 2.4gm

Now, 64 gm of Zn gives 2 gm of H₂ gas.

Therefor Amount of Zn required to produce 2.4 gm of H₂= 64/2*2.4=76.8 gm

Hence Amount of Zinc required for the given condition of reaction is 76.8gm.

Hope it Helps you!!!

The given reactions are as follows:2KClO3------> 2KCl+3O22H2+O2----> 2H2OZn+H2SO4-----> ZnSO4+H2 Now, 245 of KClO3 gives 96 g of O2Therefore O2 obtained from 24.5 gm of KClO3= 96/245*24.5= 9.6 gm of O2Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.Therefore Mass of H2 reacting with 9.6 gm of O2=4/32*9.6= 1.2gmNow, 64 gm of Zn gives 2 gm of H2 gas.Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*1.2=39 gmHence Amount of Zinc required for the given condition of reaction is 39 gm.