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24.5 gm of kclo3 heated to give o2 which on reaction with h2 horms h2o. this h2 comes from zinc and h2so4 reaction. the amount of zinc required is?
The given reactions are as follows:
2KClO3------> 2KCl+3O2
2H2+O2----> 2H2O
Zn+H2SO4-----> ZnSO4+H2
Now, 122.5 of KClO3 gives 96 g of O2
Therefore O2 obtained from 24.5 gm of KClO3= 96/122.5*24.5= 19.2 gm of O2
Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.
Therefore Mass of H2 reacting with 19.2 gm of O2=4/32*19.2= 2.4gm
Now, 64 gm of Zn gives 2 gm of H2 gas.
Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*2.4=76.8 gm
Hence Amount of Zinc required for the given condition of reaction is 76.8gm.
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