# 24.5 gm of kclo3 heated to give o2 which on reaction with h2 horms h2o. this h2 comes from zinc and h2so4 reaction. the amount of zinc required is?

18 Points
11 years ago

The given reactions are as follows:

2KClO3------> 2KCl+3O2

2H2+O2----> 2H2O

Zn+H2SO4-----> ZnSO4+H2

Now, 122.5 of KClO3 gives 96 g of O2

Therefore O2 obtained from 24.5 gm of KClO3= 96/122.5*24.5= 19.2 gm of O2

Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.

Therefore Mass of H2 reacting with 19.2 gm of O2=4/32*19.2= 2.4gm

Now, 64 gm of Zn gives 2 gm of H2 gas.

Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*2.4=76.8 gm

Hence Amount of Zinc required for the given condition of reaction is 76.8gm.

Hope it Helps you!!!

Rakesh Chandra Kalita
19 Points
6 years ago
The given reactions are as follows:2KClO3------> 2KCl+3O22H2+O2----> 2H2OZn+H2SO4-----> ZnSO4+H2 Now, 245 of KClO3 gives 96 g of O2Therefore O2 obtained from 24.5 gm of KClO3= 96/245*24.5= 9.6 gm of O2Now 32 gm of O2 react with 4gm of H2 to give 36 gm of H2O.Therefore Mass of H2 reacting with 9.6 gm of O2=4/32*9.6= 1.2gmNow, 64 gm of Zn gives 2 gm of H2 gas.Therefor Amount of Zn required to produce 2.4 gm of H2= 64/2*1.2=39 gmHence Amount of Zinc required for the given condition of reaction is 39 gm.