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1)what mass of carbon dioxide will contain same number of atoms as are contained in 20 g of oxygen? 2)how much sulphur is present in an organic compound ,if 0.53 g compound gave 1.158 g of BaSO4 on analysis?
1] 20/16*6.023*10^23=7.52*10^23atoms so7.52*10^23/6.023*10^23=1.024*10^23*44=44.924*10^23 2]
1] 20/16*6.023*10^23=7.52*10^23atoms
so7.52*10^23/6.023*10^23=1.024*10^23*44=44.924*10^23
2]
1)32g of O2= 2xNo atoms (No=avogadro no.) 20g " " =(2/32)x20 No=1.25 No atoms 44g of CO2=3xNo 1.25 No=(44/3)x1.25=18.33g of carbon dioxide 2)molar mass of BaSO4=233g no. of moles of S in compound=no. of moles of S in BaSO4=NO. OF MOLES OF BaSO4 =1.158/233 amt. of sulphur in compound=(1.158/233)x16=0.07955 I hope this will help you
1)32g of O2= 2xNo atoms (No=avogadro no.)
20g " " =(2/32)x20 No=1.25 No atoms
44g of CO2=3xNo
1.25 No=(44/3)x1.25=18.33g of carbon dioxide
2)molar mass of BaSO4=233g
no. of moles of S in compound=no. of moles of S in BaSO4=NO. OF MOLES OF BaSO4 =1.158/233
amt. of sulphur in compound=(1.158/233)x16=0.07955
I hope this will help you
As in (1) the number of moles of oxygen in 20g=5/4 moles.So, the required mass of CO2 in 5/4moles=55g.
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