+6.
This is known as peroxy di sulphuric acid(marshals acid) where peroxylinkage is there ,so six oxygen normal with -2 charge while two with -1 chrge due to peroxy linkage so sulphur oxidation number is +6 .HO-S-O-O-S-OH both sulphur attach with two cordinate oxygen atom each.
Pritish Kamath
Last Activity: 15 Years ago
0=2*1+2x+ (-2)*8
where x is the oxidation state
therefore the oxidation state is 14
correct me i i am wrong somewhere
Regards
Ramesh V
Last Activity: 15 Years ago
O.S for H is +1
O.S for O is -2
let O.S for S be x , then
2+2x-16=0
x=+7 is O.S of sulphur
anandpal shekhawat
Last Activity: 15 Years ago
Hi,
in this the two S atoms peroxy linkage between them as shown; (-S-O-O-S-) & each S has 2 double bonded O atoms & 1 -OH group. Hence, O.N. of S =+6.
Apoorv Jain
Last Activity: 14 Years ago
OXIDATION STATE OF SULPHUR IS 7
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