What is the Oxidation State of Sulphur in H 2 S 2 O 8 ??

Question

bibhash jha · Answer

+6. This is known as peroxy di sulphuric acid(marshals acid) where peroxylinkage is there ,so six oxygen normal with -2 charge while two with -1 chrge due to peroxy linkage so sulphur oxidation number is +6 .HO-S-O-O-S-OH both sulphur attach with two cordinate oxygen atom each.

Pritish Kamath · Answer

0=2*1+2x+ (-2)*8 where x is the oxidation state therefore the oxidation state is 14 correct me i i am wrong somewhere Regards

Ramesh V · Answer

O.S for H is +1 O.S for O is -2 let O.S for S be x , then 2+2x-16=0 x=+7 is O.S of sulphur

anandpal shekhawat · Answer

Hi, in this the two S atoms peroxy linkage between them as shown; (-S-O-O-S-) & each S has 2 double bonded O atoms & 1 -OH group. Hence, O.N. of S =+6.

Apoorv Jain · Answer

OXIDATION STATE OF SULPHUR IS 7

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What is the Oxidation State of Sulphur in H 2 S 2 O 8 ??

What is the Oxidation State of Sulphur in

H₂S₂O₈ ??

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What is the Oxidation State of Sulphur in H 2 S 2 O 8 ??

What is the Oxidation State of Sulphur in H2S2O8 ??

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What is the Oxidation State of Sulphur in

H₂S₂O₈ ??