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# 1 g of a mixture of carbonates of calcium and magnesium gave 240 cm3 of CO2 at STP.Calculate the percentage composition of the mixture.

Aman Bansal
592 Points
9 years ago

Dear Menka,

1g of a mixture of carbonates of calcium and magnesium gave 240 cm³ of CO2 at STP .Calculate the percentage composition of the mixture.

mass of CaCO3=x g and mass of MgCO3=(1-x) g

CaCO3 gives Cao + CO2

as 100g of CaCO3 fives 22400cm3 of CO2, therefore xg will give 22400/100*x=224x cm3

similarly, 84 g MgCO3 gives 22400 cm3 CO2, Therefore (1-x) g will give 22400/84*(1-x)=800/3*(1-x) cm3

Now, 224x+800/3*(1-x)=240.

After solving x=5/8.

% of CaCO3= 5/8*100=62.5

% of MgCO3=100-62.5=37.5

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Aman Bansal

ankitesh gupta
63 Points
8 years ago

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