Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
Imagine a atom made up of proton and a hypothetical particle of double the mass of electron but having the same charge as electrons. Apply the Bohr atokic model and consider all the possible transitions of this hypothetical particle to first excited level. The largest wavelength photon that will be emitted has wavelength (lamda) (given in terms of Rydberg constant R for the hydrogen atom) equals to: 1) 9/5R 2) 36/5R 3) 18/5R 4) 4/R
hi. rydberg const. is directely proportional to the first power of m so , rydberg const for the new atom , R' = 2R largestwavelength will be emitted in this case when the transition occurs from 3rd excited state to first 1/λ = R' { 1/2^2 - 1/3^2 } = 2R { 1/4 - 1/9 } = 5R/18 λ = 18/5R (3)
hi.
rydberg const. is directely proportional to the first power of m
so , rydberg const for the new atom , R' = 2R
largestwavelength will be emitted in this case when the transition occurs from 3rd excited state to first
1/λ = R' { 1/2^2 - 1/3^2 }
= 2R { 1/4 - 1/9 }
= 5R/18
λ = 18/5R (3)
In h-atom; E(n)=-Rhc/(n*n) Also, E(n) is proportional to m m is mass of electron. As m-->2m, E(n)=-2Rhc/(n*n) for largest wavelength(x), 1/x=R((1/4)-(1/9)) x=18/5R Hence (C)
In h-atom;
E(n)=-Rhc/(n*n)
Also, E(n) is proportional to m
m is mass of electron.
As m-->2m, E(n)=-2Rhc/(n*n)
for largest wavelength(x), 1/x=R((1/4)-(1/9))
x=18/5R
Hence (C)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -