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How to find n factor of HI in following redox reaction: Cr 2 O 7 2- + HI -------------- KI + CrI 3 + I 2 + H 2 O Please Help

How to find n factor of HI in following redox reaction:


Cr2O72- + HI -------------- KI + CrI3 + I2 + H2O


 


Please Help

Grade:11

2 Answers

vivek raj
14 Points
9 years ago

0 because initially oxidation state of I in HI is -1 and after rxn in both compound KI and CrI3 its oxidation state is -1

SUDEEP KUMAR SAHU
18 Points
9 years ago

Here the n factor is 10.

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