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Grade: 11
        Two moles HI were heated in a sealed tube at 440C till the equilibrium was reached.HIwas found to be 22% decomposed.The equilibrium constant for dissociation is?
10 years ago

Answers : (1)

pratham ashish
9 Points
							

Hi,

there r 2of eq. constant

K& K

           rxn       2HI -> H2 +I2

  moles initally   2        0     0

moles @eqlb.   2-2x    x      x   

   

                                Kc   =  x*x/{2-2x}^2 = (0.22)^2/4*(0.78)^2 = 0.19888

 

conc.(C)= P/RT  for gas phase rxn 

                                         RT *(x)= PH2 = PI2   = 0.19888        (same as   Kc bcz  power o RT cancel out  )

                            

                                             

 


10 years ago
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