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Two moles HI were heated in a sealed tube at 440C till the equilibrium was reached.HIwas found to be 22% decomposed.The equilibrium constant for dissociation is?
Hi, there r 2of eq. constant Kc & Kp rxn 2HI -> H2 +I2 moles initally 2 0 0 moles @eqlb. 2-2x x x Kc = x*x/{2-2x}^2 = (0.22)^2/4*(0.78)^2 = 0.19888 conc.(C)= P/RT for gas phase rxn RT *(x)= PH2 = PI2 = 0.19888 (same as Kc bcz power o RT cancel out )
Hi,
there r 2of eq. constant
Kc & Kp
rxn 2HI -> H2 +I2
moles initally 2 0 0
moles @eqlb. 2-2x x x
Kc = x*x/{2-2x}^2 = (0.22)^2/4*(0.78)^2 = 0.19888
conc.(C)= P/RT for gas phase rxn
RT *(x)= PH2 = PI2 = 0.19888 (same as Kc bcz power o RT cancel out )
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