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A metal oxide is reduced by heating it in a stream of hydrogen.It is found that after compelete reduction 3.15g of the oxide have yielded 1.05g of the metal.We may conclude that A metal oxide is reduced by heating it in a stream of hydrogen.It is found that after compelete reduction 3.15g of the oxide have yielded 1.05g of the metal.We may conclude that
consider +1 and +2 oxidation states for metals case 1 : M2O + H2 -- > 2M +H2O 2x+16 2x so, its , 2*3.15/(2x+16) = 1.05/x or x= 4 i.e., the compound may be Helium(but helium being inert gas doesn't for oxide) case 2 : MO + H2 -- > M +H2O x+16 x so, its , 3.15/(x+16) = 1.05/x or x = 8 (but there is no element with atomic weight of 8) -- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Ramesh
consider +1 and +2 oxidation states for metals
case 1 :
M2O + H2 -- > 2M +H2O
2x+16 2x
so, its , 2*3.15/(2x+16) = 1.05/x
or x= 4 i.e., the compound may be Helium(but helium being inert gas doesn't for oxide)
case 2 :
MO + H2 -- > M +H2O
x+16 x
so, its , 3.15/(x+16) = 1.05/x
or x = 8 (but there is no element with atomic weight of 8)
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Ramesh
actually it can be much more easier . we all know that there is no metal with atomic mass of 8 and helium doesn’t form oxide . so the answer can be calculated by the following method:mass of metal/massof oxygen(both given in ques.)= eq. mass of metal (E) /eq.mass of oxygen (i.e.8)1.05 / (3.15-1.05) =E/8E=4
Simply apply the relationship between equivalent wt. And mass of element i.e.Mass of element/eq.of element=mass of oxid
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