2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

Question

JAGABANDHU PANDA · Answer

Elements Given mass % Atomic mass Moles Mole ratio Whole no. ratio P 1.24g 56.4 30.974 1.8 1.3 13 S 0.96 43.6 32.065 1.4 1 10 So the empirical formula is P 13 S 10

Ramesh V · Answer

atomic weight of P : 31 and S :32

wt of P:1.24g and wt pf : 0.96g

ratio of moles of P:S = (1.24/31) : (0.96/32)

= 4:3

empirical formula is : nP₄S₃

--

Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and
we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Naga Ramesh
IIT Kgp - 2005 batch

Vaibhav · Answer

Ratio of P and the compound is 1.24 to 2,2 is 0.564In compound P4S3 , mass of P is 124g and total mass of P4S3 is 220. Ratio is 124/220 =0.564So, answer is option3, P4S3.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

3 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Physical Chemistry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship