# 2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

JAGABANDHU PANDA
8 Points
14 years ago

 Elements Given mass % Atomic mass Moles Mole ratio Whole no. ratio P 1.24g 56.4 30.974 1.8 1.3 13 S 0.96 43.6 32.065 1.4 1 10

So the empirical formula is P13S10

Ramesh V
70 Points
14 years ago

atomic weight of P : 31  and S :32

wt of P:1.24g and wt pf : 0.96g

ratio of moles of P:S = (1.24/31) : (0.96/32)

= 4:3

empirical formula is : nP4S3

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Vaibhav
24 Points
6 years ago
Ratio of P and the compound is 1.24 to 2,2 is 0.564In compound P4S3 , mass of P is 124g and total mass of P4S3 is 220. Ratio is 124/220 =0.564So, answer is option3, P4S3.