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Grade: 12
        2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.
10 years ago

Answers : (3)

JAGABANDHU PANDA
8 Points
							

Elements

Given mass

%

Atomic mass

Moles

Mole ratio

Whole no. ratio

P

1.24g

56.4

30.974

1.8

1.3

13

S

0.96

43.6

32.065

1.4

1

10

So the empirical formula is P13S10

10 years ago
Ramesh V
70 Points
							

atomic weight of P : 31  and S :32

wt of P:1.24g and wt pf : 0.96g

ratio of moles of P:S = (1.24/31) : (0.96/32)

                                     = 4:3

empirical formula is : nP4S3

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10 years ago
Vaibhav
24 Points
							Ratio of P and the compound is 1.24 to 2,2 is 0.564In compound P4S3 , mass of P is 124g  and total mass of P4S3 is 220.  Ratio is 124/220 =0.564So, answer is option3, P4S3.
						
2 years ago
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