Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

Grade:12

3 Answers

JAGABANDHU PANDA
8 Points
11 years ago

Elements

Given mass

%

Atomic mass

Moles

Mole ratio

Whole no. ratio

P

1.24g

56.4

30.974

1.8

1.3

13

S

0.96

43.6

32.065

1.4

1

10

So the empirical formula is P13S10

Ramesh V
70 Points
11 years ago

atomic weight of P : 31  and S :32

wt of P:1.24g and wt pf : 0.96g

ratio of moles of P:S = (1.24/31) : (0.96/32)

                                     = 4:3

empirical formula is : nP4S3

--

Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and
we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Naga Ramesh
IIT Kgp - 2005 batch
 

Vaibhav
24 Points
4 years ago
Ratio of P and the compound is 1.24 to 2,2 is 0.564In compound P4S3 , mass of P is 124g and total mass of P4S3 is 220. Ratio is 124/220 =0.564So, answer is option3, P4S3.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free