2.2g of a compound of phosphorous and sulphur has 1.24g of P in it.Determineits empirical formula.

So the empirical formula is P₁₃S₁₀

atomic weight of P : 31  and S :32

wt of P:1.24g and wt pf : 0.96g

ratio of moles of P:S = (1.24/31) : (0.96/32)

                                     = 4:3

empirical formula is : nP₄S₃

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