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Electrolysis of KBr(aq) gives Br 2 at anode but of KF(aq) does not give F 2 . Give reason for disparity in behaviour.

Electrolysis of KBr(aq) gives Br2 at anode but of KF(aq) does not give F2. Give reason for disparity in behaviour.

Grade:12

1 Answers

askiitian.expert- chandra sekhar
10 Points
11 years ago

Hi Belani,

The activities of the anion based on EOP follows the order:

F- > OH- > Cl- > Br- > I-

At anode least active anion is deactivated.

In aq. solution OH- is present.

So in the electrolysis of KBr(aq), Br- will be deactivated. While in the electrolysis of KF(aq), OH-will be deactivated.

askiitian.expert- chandra sekhar

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