Mass of one e = 9.1*10^-31No of e in 1 kg = 1/9.1*10^-31Miles of e =no of moles/NA =1/9.1*10^-31* NA=1/9.1*6.022. * 10^8
Niraj
Last Activity: 7 Years ago
9.108 * 10^-31 Kg = 1 electron1kg = 1.098 * 10^30 electrons6.022*10^23 electrons=1 mole of electron1.098*10^30 electrons=1.823*10^6 molesTherefore the answer is -1.823*10^6 moles
ankan sen
Last Activity: 7 Years ago
9.1101* 10^-31 kg contains 1 electron .
therefore, 1 kg will contain 1/(9.1101 * 10 ^ -31 electrons)
which is equal to 1/(9,1101 * 10 ^ -31)(6.022 * 10 ^ 23) MOLES OF ELECTORN
WHICH IS EQUAL TO 10^8/(9.011*6.022) MOLES
9.108 * 10^-31 Kg = 1 electron1kg = 1.098 * 10^30 electrons6.022*10^23 electrons=1 mole of electron1.098*10^30 electrons=1.823*10^6 molesTherefore the answer is -1.823*10^6 moles
Rajeev Lochan Muduli
Last Activity: 7 Years ago
mass of 1 mole of electron= 6.023*10^23*9.108*10^-31 kg
( since, 6.023*10^23*9.108*10^-31 kg=mass of 1 mole of electron)
therefore,
1*10^8
1kg=----------------- moles = 1.822921*10^6
6.023*9.108
Rishi Sharma
Last Activity: 4 Years ago
Dear Student, Please find below the solution to your problem.
9.1101* 10^-31 kg contains 1 electron .therefore, 1 kg will contain 1/(9.1101 * 10 ^ -31 electrons)which is equal to 1/(9,1101 * 10 ^ -31)(6.022 * 10 ^ 23) MOLES OF ELECTORNWHICH IS EQUAL TO 10^8/(9.011*6.022) MOLES 9.108 * 10^-31 Kg = 1 electron1kg = 1.098 * 10^30 electrons6.022*10^23 electrons=1 mole of electron1.098*10^30 electrons=1.823*10^6 molesTherefore the answer is -1.823*10^6 moles
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