Q80. A 0.6 % solution of urea (molecular weight 60) would be isotonic with A 0.6% glucose solution B 0.6% KCl solution C 0.1M glucose solution D 0.1M KCl solution How do i find the ans for this problem!!!!

Question

jophin joy · Answer

here molarity of given data i.e.0.6% solution urea=0.1 M by d formula M=10x/Mol Wt. (x=given %) i.e. 0.6*10/60 now verifiy wid d given options.... 0.1 M gulcose is isotonic. KCl is ionic so it dissociates and 0.6% glucose=0.03 M i hope its correct...:)

Sohan · Answer

0.6%of urea is .6 gms in 100 ml which is equal to 6 gms in 1000ml Hence molarity wuld be 6/60/1 liter i.e 0.1 M Osmotic pressure is directly prop. to conc. Hence if osmotic pressure are equal their conc shuld be equal therfore it is c 0.1 M glucose soln

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Q80. A 0.6 % solution of urea (molecular weight 60) would be isotonic with A 0.6% glucose solution B 0.6% KCl solution C 0.1M glucose solution D 0.1M KCl solution How do i find the ans for this problem!!!!

Q80. A 0.6 % solution of urea (molecular weight 60) would be isotonic with

A 0.6% glucose solution

B 0.6% KCl solution

C 0.1M glucose solution

D 0.1M KCl solution

How do i find the ans for this problem!!!!

2 Answers

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