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How do i calculate the number of bond pairs and lone pairs in CH4 (Methane) and NH3 (Ammonia). Explain it please...
in CH4 , valence electrons of carbon are 4 , it forms 4 bonds by sharing 1 electron with each hydrogen... now all four electrons are utilised in sharing so no electron is left ... lone pair(pair of non bonding electron) = 0 in NH3 , valence electrons of N are 5 , 3 electrons are shared with 3 hydrogen so total electrons remaining with N are 2 ... lone pair = 1 total number of bonds = bond paires for NH3 , bond pairs = 3 for CH4 , bond pairs = 4
in CH4 , valence electrons of carbon are 4 , it forms 4 bonds by sharing 1 electron with each hydrogen...
now all four electrons are utilised in sharing so no electron is left ...
lone pair(pair of non bonding electron) = 0
in NH3 , valence electrons of N are 5 , 3 electrons are shared with 3 hydrogen so total electrons
remaining with N are 2 ...
lone pair = 1
total number of bonds = bond paires
for NH3 , bond pairs = 3
for CH4 , bond pairs = 4
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