Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

Grade:11

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Let,

The mass of the organic compound taken be = W g

Volume of air displaced = V1 mL

Atmospheric pressure = P mm of Hg

Room temperature, T1 = toC = (t + 273)K

Aqueous tension at toC = p mm of Hg

Pressure of the dry air, P1 = (P-p) mm Hg

volume of dry air at NTP

The volume of the displaced air is equal to the volume of vapors formed from the given mass of the compound. So, by using the mole concept, one can write,

V mL of vapour weigh = W g

Therefore,

kiran kumar pidikiti
15 Points
10 years ago

VOLUME OCCUPIED BY 0.23 GM OF THE SUBSTANCE IS 112ML AT STP GIVEN

THEREFORE  WT OF I MOLE OF THE SUBSTANCE IS WQUAL TO    22400  X  .23   /  112   

THAT IS    MOLECULAR WEIGHT OF THE SUBSTANCE         =   46

AND ITS VAPOUR DENSITY IS EQUAL TO     46/2    -     23   

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free