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Grade: 11

                        

In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

9 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

Let,

The mass of the organic compound taken be = W g

Volume of air displaced = V1 mL

Atmospheric pressure = P mm of Hg

Room temperature, T1 = toC = (t + 273)K

Aqueous tension at toC = p mm of Hg

Pressure of the dry air, P1 = (P-p) mm Hg

volume of dry air at NTP

The volume of the displaced air is equal to the volume of vapors formed from the given mass of the compound. So, by using the mole concept, one can write,

V mL of vapour weigh = W g

Therefore,

9 years ago
kiran kumar pidikiti
15 Points
							

VOLUME OCCUPIED BY 0.23 GM OF THE SUBSTANCE IS 112ML AT STP GIVEN

THEREFORE  WT OF I MOLE OF THE SUBSTANCE IS WQUAL TO    22400  X  .23   /  112   

THAT IS    MOLECULAR WEIGHT OF THE SUBSTANCE         =   46

AND ITS VAPOUR DENSITY IS EQUAL TO     46/2    -     23   

9 years ago
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