In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

Dear student,

Let,

The mass of the organic compound taken be = W g

Volume of air displaced = V₁ mL

Atmospheric pressure = P mm of Hg

Room temperature, T₁ = t^oC = (t + 273)K

Aqueous tension at t^oC = p mm of Hg

Pressure of the dry air, P₁ = (P-p) mm Hg

The volume of the displaced air is equal to the volume of vapors formed from the given mass of the compound. So, by using the mole concept, one can write,

V mL of vapour weigh = W g

Therefore,

Approved

VOLUME OCCUPIED BY 0.23 GM OF THE SUBSTANCE IS 112ML AT STP GIVEN

THEREFORE  WT OF I MOLE OF THE SUBSTANCE IS WQUAL TO    22400  X  .23   /  112   

THAT IS    MOLECULAR WEIGHT OF THE SUBSTANCE         =   46

AND ITS VAPOUR DENSITY IS EQUAL TO     46/2    -     23?   

Approved