In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

Question

SAGAR SINGH - IIT DELHI · Answer

Dear student,

Let,

The mass of the organic compound taken be = W g

Volume of air displaced = V₁ mL

Atmospheric pressure = P mm of Hg

Room temperature, T₁ = t^oC = (t + 273)K

Aqueous tension at t^oC = p mm of Hg

Pressure of the dry air, P₁ = (P-p) mm Hg

The volume of the displaced air is equal to the volume of vapors formed from the given mass of the compound. So, by using the mole concept, one can write,

V mL of vapour weigh = W g

Therefore,

kiran kumar pidikiti · Answer

VOLUME OCCUPIED BY 0.23 GM OF THE SUBSTANCE IS 112ML AT STP GIVEN

THEREFORE WT OF I MOLE OF THE SUBSTANCE IS WQUAL TO 22400 X .23 / 112

THAT IS MOLECULAR WEIGHT OF THE SUBSTANCE = 46

AND ITS VAPOUR DENSITY IS EQUAL TO 46/2 - 23?

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In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

In Victor meyers experiment, 0.23gram of a volatile solute displaced air which measures 112ml at 1 atm and 273k. Calculate vapour density and molecular weight of a substance

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