initial volume of sol = 0.1

moles/V = M

moles = MV                   (M molality & V volume in liters)

moles of solute = 0.1*0.01 = .01

let volume of water added = V litre then final vol will be (0.1+V)

finall molarity = moles/volume = 0.01/(0.1+V) , this should be equal to 0.01

       0.001/(0.1+V) = 0.01

           V = 0.9L=900ml        ans

approve if u like it

900ML

Dear student,

Use molarity=moles/volume of the solution

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