vikas askiitian expert
Last Activity: 13 Years ago
initial volume of sol = 0.1
moles/V = M
moles = MV (M molality & V volume in liters)
moles of solute = 0.1*0.01 = .01
let volume of water added = V litre then final vol will be (0.1+V)
finall molarity = moles/volume = 0.01/(0.1+V) , this should be equal to 0.01
0.001/(0.1+V) = 0.01
V = 0.9L=900ml ans
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