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Grade: 12 

                        
Why an elementary reaction becomes second order reaction at low pressure?
9 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points 
							
Dear student,


A second-order reaction depends on the concentrations of one second-order reactant, or two first-order reactants.


For a second order reaction, its reaction rate is given by:


\ -\frac{d[A]}{dt} = 2k[A]^2 or \ -\frac{d[A]}{dt} = k[A][B] or \ -\frac{d[A]}{dt} = 2k[B]^2


In several popular kinetics books, the definition of the rate law for second-order reactions is -\frac{d[A]}{dt} = k[A]^2.  Conflating the 2 inside the constant for the first, derivative, form  will only make it required in the second, integrated form.


 


































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Sagar Singh


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9 years ago
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