Guest

CHEMISTRY For 3s orbital of hydrogen atom, the normalised wave function is given by y3s = {1/[81(3 pie)^1/2} * (1/a)^3/2 * [27 - (18r)/a + (r)^2/(a)^2] * e^r/3a The above mentioned orbital (3s) has two nodes at 1.9a0 and xa0. What is the approximate value of x? (a) 9 (b) 7 (c) 6 (d) 2

CHEMISTRY
For 3s orbital of hydrogen atom, the normalised wave function is given by

y3s = {1/[81(3 pie)^1/2} * (1/a)^3/2 * [27 - (18r)/a + (r)^2/(a)^2] * e^r/3a

The above mentioned orbital (3s) has two nodes at 1.9a0 and xa0. What is the approximate value of
x?
(a) 9 (b) 7
(c) 6 (d) 2

Grade:11

2 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

To get the value of x, put the normalised wave function to be zero. This is just a hint, u can solve the equation on ur own..

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

 

Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

sagarsingh24.iitd@gmail.com

Pankaj Rajpal
13 Points
5 years ago
A node is where it goes to zero; BTW it must be e^(MINUS r/3ao) otherwise it blows up 


in this case ignore everything but [ 27- 18r/a0 + 2r^2/a0^2] 
By solving this quadratic equation we get the two answer from which we can find the values of nodes 


1.90 

7.10 

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free