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Find the pH and % dissociation of HAc in a solution obtained by mixing 25ml of 0.2M HCl and 25ml of 0.2M NaAc. Given Ka for HAc is 1.78*10-5
HCl + CH3COONA => CH3COOH + NaCl
25*0.2 (millimoles) 25*0.2(mllimoles) => 0 0 (initial)
0 0 25*0.2 25*0.2 (final)
total millimoles of acetic acid = 25*0.2
total volume = 50ml
molarity of acetic acid (C)= 25*0.2/50=0.1
degree of dissotiation = (Ka/c)1/2 = (1.78*10-4)1/2
=1.33%
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