 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
0.96g of H ydrogen iodide was heated to 450 degree centigrade till the equilibrium was reached.It was then quickly cooled and the amount of iodine formed required 15.7ml of N/10 Na 2 S 2 O 3 . Calculate the degree of dissociation of HI at 450 degree centigrade

```
9 years ago

```							Dear student,
I will give u a hint regarding this:
The degree of dissociation of PCl5 at a certain  temperature and under atmospheric pressure is 0.2. Calculate the  pressure at which it will be half dissociated at the same temperature.
PCl5 dissociates as: PCl5 ? PCl3 Cl2 If α is the degree of dissociation at certain temperature under atmospheric pressure, then Initial concentration: PCl5 = 1 PCl3 = 0 Cl2 = 0 At Equilibrium: PCl5 = 1 – α PCl3 = α Cl2 = α Total number of moles at equilibrium = 1 – α + α + α = 1 + α Partial pressures of PCl5, PCl3 and Cl2 will be: p (PCl3) = α p / 1 + α p (Cl2) = α p / 1 + α p (PCl5) = (1 – α) p / 1 + α Kp = p (PCl3) X p (Cl2) / p (PCl5) Kp = [(α p / 1 + α) X (α p / 1 + α)]/[ (1 – α) p / (1 + α)] = α2 p / (1 – α) 2 Substituting p = 1 atm and α = 0.2 Kp = (0.2) 2 X 1 / (1 – (0.2)) 2 = 0.041 When α = 1/2 = 0.5, let pressure is p’ Kp = α2 p’ / (1 – α) 2 0.041 = (0.5) sup>2 p’ / (1 – (0.5)) 2 p’ = (0.041) [1 – (0.5) 2] / (0.5) 2 p’ = 0.125 atm

All the best.
Win exciting gifts by                                                                                                              answering     the            questions       on                       Discussion                 Forum.      So                help                          discuss             any                             query      on                     askiitians            forum      and                 become     an              Elite                          Expert            League                              askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
9 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions