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To 250ml of M/50 sulphuric acid, 4g of solid sodium hydroxide is added and the resulting solution is diluted to 1litre. Determine the pH of the resulting solution

debadutta mishra , 15 Years ago
Grade 11
anser 2 Answers
SAGAR SINGH - IIT DELHI

Dear student,

First of all determine teh equivalents of NaOH required to neutralise sulphuric acid and then we can get concentration of H+

take -logarithm of H+ to calculate pH of the resulting solution...

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Sagar Singh

B.Tech, IIT Delhi

Last Activity: 15 Years ago
Devender Chopra
Moles of H2SO4 = n factor × Conc.×Volume
                                =  2×1/50×250/1000 
                                 =0.01 moles
Moles of NaOH = given mass / molar mass
                              =  4/40 = 0.1 moles 
Moles left of NaOH = 0.1-0.01 = 0.09 
                         [OH-] = 0.09 
pOH = -log(0.09) = 1.045
pH = 14-1.045 = 12.95 ← Ans.
 
Last Activity: 4 Years ago
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