#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# the angular momentum of an electron in 2s orbit is?

419 Points
10 years ago

Dear Pankaj

$L = n{h \over 2\pi} = n\hbar$
n=2
L=h/∏

All the best.

AKASH GOYAL

Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

rajan jha
49 Points
10 years ago

angular momentum(mvr)=h/2pi(l(l+1))1/2

=h/2pi(0(0+1))1/2             {for 2s orbital l=0}

=0

509 Points
10 years ago

according to bohr's theory ,angular momentam of electron is mvr =nh/2pi

angular momentam =nh/2pi

for 2s orbital value of principal quantam number (n) is 2

therefore angular momentam of electron is 2h/2pi= h/pi....