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what is the final concentration of all the ions when when following are mixed:-50ml of .12M Fe(no3)3 ,100ml of .10M Fecl3 and 100ml of .26M Mg(no3)2??
dear Akhilesh,
Molarity = moles of solute/ volume of solution(lit.)
1) moles of Fe(no3)3 = .12×50/1000
1 mole of Fe(no3)3 contains 4 ions
therefore .12×50/1000 contains = .12×50/1000×4 ions
=.024 ions
2) moles of Fecl3 = 100×.10/1000
therefore 100×.10/1000 contains = 100×.10/1000×4 ions
=.040 ions
3) in the same way moles of Mg(no3)2 = 100×.26/1000
and ions = 100×.26/1000×3
=.078 ions
Total ions = .024+.040+.078
=.142
Total concentration of ions = total moles/ total volume(lit.)
=.142/.25
=.568 M
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