Please explain me Principle of atom conservation in detail and the kind of questions that can be asked from this topic.

Dear rishabh,

The principle implies Number of atoms remains constant. Lets understand this with an example.

1g of a mixture of cuprous oxide and cupric oxide was quantitatively reduced to 0.839 g of metallic copper. what is the weight of cupric oxide in the original sample.

The solution is:

63.563 + 16 = 79.563
127.126 + 16 = 143.126
x*79.563 + y*143.126 = 1
x*63.563 + y*127.126 = 0.839
x = 0.006925497
x*79.563 = 0.551 g cupric oxide

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

Sir,

I didn't understand the last three steps of the example....plz explain me in detail.