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calculate the emf of following concentration cell.
Ag/Ag+(0.1M)//Ag/Ag+(1.0M)
Dear sid,
Ag+(aq) + 2e- -> Ag(s) E0 +0.80V Ni(s) -> NI2+(aq) + 2e- E0 -0.28V 2Ag + Ni -> Ag + Ni2+ E0 0.52V
We are all IITians and here to help you in your IIT JEE preparation. All the best. If you like this answer please approve it.... win exciting gifts by answering the questions on Discussion Forum Sagar Singh B.Tech IIT Delhi sagarsingh24.iitd@gmail.com
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