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1.5gm of a monobasic acid when disslved in 150g of water lowers Frezing pt by 0.165 degrees celsius.0.5g of same acid when titrated,after dissolution in water, requires 37.5ml of N/10 alkali.Calculate degree of dissociation of acid(If Kf of water is 1.86)

Chilukuri Sai Kartik , 14 Years ago
Grade 12
anser 3 Answers
SAGAR SINGH - IIT DELHI

Last Activity: 14 Years ago

Dear student,

Freezing point depression can be calculated using the Clausius-Clapeyron equation and Raoult's law. In a dilute ideal solution the freezing point is:

Freezing Pointtotal = Freezing Pointsolvent - ΔTf

where ΔTf = molality * Kf * i

Kf = cryoscopic constant (1.86°C kg/mol for the freezing point of water)

i = Van't Hoff factor

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Sagar Singh

B.Tech, IIT Delhi

Sourabh Dhavala

Last Activity: 11 Years ago

The answer is 18.34%. I''m not getting that answer. 

tanay

Last Activity: 5 Years ago

∆Tb=(W2 *1000)/(Mw2  × W1)
0.168=(1.86 X 1000)/(M X 100)
M = 11 0.71
 
N1 xV1   = N2 x V2 
15.1/10 =(0.2×1000)/M.M   (equivalent)
= 132.45
i= 132.45× 110.71 = 1+ a            HX= H+ + X-
alpha= 19.6

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