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K.E. of the electron is . Its de Broglie wave length is

K.E. of the electron is . Its de Broglie wave length is

Grade:12

1 Answers

AskiitiansExpert Abhinav Batra
25 Points
11 years ago

Dear Rahul

we now from the de brogelie` law

p=h/λ

but p2/2m=K.E.

so p=√2mK.E.

so √2mK.E.=h/λ

hence λ=h/√2mK.E.=√(hπ/m) where m iS the maSS of electron

SubStituting the valueS h=6.626*10-34 m=9.1*10-31 π=22/7

λ=4.78*10-2 m

ALL THE best

AskIITIANsExpert

ABhinav Batra



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