K.E. of the electron is . Its de Broglie wave length is
Dear Rahul
we now from the de brogelie` law
p=h/λ
but p2/2m=K.E.
so p=√2mK.E.
so √2mK.E.=h/λ
hence λ=h/√2mK.E.=√(hπ/m) where m iS the maSS of electron
SubStituting the valueS h=6.626*10-34 m=9.1*10-31 π=22/7
λ=4.78*10-2 m
ALL THE best
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ABhinav Batra
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