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A mixture of ordinary hydrogen atom and tritium, a hydrogen isotope whose nucleus is approximately 3 times more massive than ordinary hydrogen, is excited and spectrum is observed . How far in wavelength will the Hinfinity lines of the to kinds of hydrogen be?

sanket sit , 16 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To understand how the wavelengths of the hydrogen and tritium spectral lines differ, we need to delve into the concept of the Rydberg formula, which describes the wavelengths of spectral lines in hydrogen-like atoms. The key here is to recognize how the mass of the nucleus affects the energy levels of the electrons in these atoms.

The Rydberg Formula

The Rydberg formula for the wavelengths of spectral lines in hydrogen is given by:

1/λ = RZ²(1/n₁² - 1/n₂²)

Where:

  • λ is the wavelength of the emitted or absorbed light.
  • R is the Rydberg constant (approximately 1.097 x 10⁷ m⁻¹ for hydrogen).
  • Z is the atomic number (1 for hydrogen and tritium).
  • n₁ and n₂ are the principal quantum numbers of the electron's energy levels.

Mass and Energy Levels

In hydrogen, the nucleus consists of one proton, while tritium has one proton and two neutrons, making it about three times more massive than ordinary hydrogen. This increased mass affects the energy levels of the electron due to the reduced mass effect.

The reduced mass (μ) of the electron in a hydrogen-like atom can be calculated using the formula:

μ = (mₑ * M) / (mₑ + M)

Where:

  • mₑ is the mass of the electron.
  • M is the mass of the nucleus (1 for hydrogen and approximately 3 for tritium).

Calculating the Wavelength Shift

For hydrogen, the reduced mass is approximately equal to the mass of the electron, while for tritium, the reduced mass will be slightly less due to the heavier nucleus. This change in reduced mass will affect the energy levels and, consequently, the wavelengths of the emitted light.

To find the difference in wavelengths for the Hα line (n₁ = 2, n₂ = 3), we can express the wavelengths for both hydrogen and tritium:

  • For hydrogen: 1/λₕ = R(1/2² - 1/3²)
  • For tritium: 1/λₜ = R(1/2² - 1/3²) * (μₜ/μₕ)

Since the Rydberg constant is the same for both, the difference in wavelengths will primarily come from the reduced mass ratio:

Δλ = λₜ - λₕ

Example Calculation

Let’s say we calculate the wavelengths for the Hα line:

  • For hydrogen, using the Rydberg formula, we find λₕ ≈ 656 nm.
  • For tritium, we would find λₜ to be slightly longer due to the reduced mass effect.

Thus, the difference in wavelengths can be calculated, and you would find that the tritium line is shifted to a longer wavelength compared to the ordinary hydrogen line.

Summary of Findings

The wavelengths of the spectral lines for hydrogen and tritium differ due to the mass of the nucleus affecting the reduced mass of the electron. This results in a shift in the energy levels and, consequently, the wavelengths of emitted light. The tritium lines will be longer than those of ordinary hydrogen, illustrating the fascinating interplay between mass and atomic structure in quantum mechanics.

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