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What is the mass percent of Fe3+ ions in Fe0.93O1.00(the numbers 0.93 and 1.00 are subscripts). please help

K. Mohmmed Laique Hussain , 15 Years ago

Grade

3 Answers

Askiitians Expert Sahil Arora - IITD

Last Activity: 15 Years ago

Dear Student ,

let out of 0.93, Fe³⁺=x and Fe²⁺=.93-x

then using charge balance..

3*x+2*(0.93-x)=2*1

( 1 for oxygen)

x=.14

% of Fe³⁺=(.14/.93)*100=15%

All the best K.Mohammed





Regards,

Askiitians Experts

Sahil Arora

Approved

Sameer

Last Activity: 6 Years ago

We have to find Fe3+% in the compound not in individual Fe component of the compound.

Let 1mole of Fe0.93O

Moles of Fe=0.93

Moles of O= 1

Let Moles of Fe3+=a

And Moles of Fe2+=0.93-a

Charge on whole compound(i.e in 1 mole)=

a×(+3)×Ń+0.93-a(+2)×Ń+1×(-2)×Ń=0

a=0.14

%Fe3+ inFe0.93O=Weight of (Fe3+)÷Total weight of compound ×100

= 0.14×56

------------------------ ×100 = 11.515

0.93×56+16×1

Rishi Sharma

Last Activity: 5 Years ago

Hello K Mohmmed,
The solution of above problem is as follows
let out of 0.93, Fe3+=x and Fe2+=.93-x
then using charge balance..
3*x+2*(0.93-x)=2*1( 1 for oxygen)
x=.14
% of Fe3+=(.14/.93)*100=15%
Thanks
I hope above solution will clear your all doubts.
Please feel free to post and ask as much doubts as possible.
All the best.