If the dissociation constant of HCN is 4.8 X 10-10mol dm-3, then the pH of 0.25 mol dm-3NaCN solution is

Put K_a=4.8 X 10^-10 mol dm^-3 and C=0.25 mol/dm³.

we get pH=8.55

for more details read:-

http://www.askiitians.com/iit-jee-chemistry/physical-chemistry/salt-of-weak-acid-and-strong-base.aspx

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