18 m solution of sulphuric acid was diluted to 1000 l. Find the normality of solution.
Ishan karki , 6 Years ago
Grade 12th pass
Inorganic Chemistry> 18 m solution of sulphuric acid was dilut...
1 Answers
Arun
Last Activity: 6 Years ago
Change in molarity after dilution =
M1V1 = M2V2
18 M x 1L = M2 x 1000 L
M2 = 18M x 1L/1000 L
= 0.018 M
Now,
Normality = n x Molarity
n- no. of replaceble ion i.e 2 ( H2SO4 produce two H+ ions )
N = 2 x 0.018 = 0.036 N
M1V1 = M2V2
18 M x 1L = M2 x 1000 L
M2 = 18M x 1L/1000 L
= 0.018 M
Now,
Normality = n x Molarity
n- no. of replaceble ion i.e 2 ( H2SO4 produce two H+ ions )
N = 2 x 0.018 = 0.036 N
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