Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

15ml of a gaseous hydrocarbon was required for complete combustion in 357ml of air (21% of oxygen by volume ) and the gaseous products occupied 327ml (all volumes being measured at NTP) . what is the formula of hydrocarbon?

15ml of a gaseous hydrocarbon was required for complete combustion in 357ml of air (21% of oxygen by volume ) and the gaseous products occupied 327ml (all volumes being measured at NTP) . what is the formula of hydrocarbon?

Grade:upto college level

1 Answers

debasish mohanta
19 Points
4 years ago

CxHy + (2x+y/2)/2 O2 → xCO2 + y/2 H2O
Find the volume of O2 used = 75ml..
Volume of CxHy = 15ml
that means 4x + y = 20
so possible values of x and y
x y
3 8
15 ml of CxHy will produce 45 ml of CO2
volume of product = volume of CO2 + volume of left over air
327 = volume of CO2 + 357 - 75
volume of CO2 = 45ml
that means x = 3..so the case we took is ryt..hence the answer is C3H8

PS : The trick in the problem is that..water will not be in gaseous form at NTP

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free