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Grade: 11

                        

150ml of ozonised oxygen was passed through a red hot tube and the volume increases by 10ml calculate the percentage of ozone in the mixture

5 months ago

Answers : (1)

Arun
24734 Points
							
100 ml of mixture contain O3 and O2.Turpentine oil absorb only O3.Since reduction in volume is 20 mL indicates that mixture contain 20 mL of O3. It means 100 mL of mixture contains 20 ml O3 and 80 ml O2.On Heating O3 decomposed as follows :2O3 →​ 3O22 ml O3 gives 3 ml O2Therefore 20 mL of O3 would give 30 mL of O2​Total volume of mixture after heating​80 mL of O2 + 30 mL of O2 = 110 mL​The total increase in volume = 110mL-100 mL​ = 10 mL
5 months ago
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