100 ml of a buffer solution contains 0.1 M each o

Question

100 ml of a buffer solution contains 0.1 M each of weak acid HA and salt NaA . How many grams of NaOH should be added to the buffer so that it's pH will be 6? ( Ka of HA = 10^-5

Vikas TU · Accepted Answer

We know the formula to find the concentration of a buffer in case of weak acid and strong base.pH= pKa+log([salt]/[acid])It is given that the concentration of salt and acid is 0.1M and that Ka is 10^-5.So pH of the buffer is 5.Now we have to make the pH 6.Let the concentration of NaOH added be x in the given 100ml. HA is in equilibrium with H+ + A- Since Ka remains same and the desired pH is 6 10^-5=(10^-6*[0.1+x])/10^-1We get x to be 0.9.So the weight of NaOH required would be 3.6grams.

Inorganic Chemistry> 100 ml of a buffer solution contains 0.1 ...

100 ml of a buffer solution contains 0.1 M each of weak acid HA and salt NaA . How many grams of NaOH should be added to the buffer so that it's pH will be 6? ( Ka of HA = 10^-5

Akarsh Raj , 6 Years ago

Vikas TU

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Inorganic Chemistry> 100 ml of a buffer solution contains 0.1 ...

100 ml of a buffer solution contains 0.1 M each of weak acid HA and salt NaA . How many grams of NaOH should be added to the buffer so that it's pH will be 6? ( Ka of HA = 10^-5

Akarsh Raj , 6 Years ago

Vikas TU

LIVE ONLINE CLASSES

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