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10 ml of H2O2 solution reacts with KI solution to produce 0.5gm of iodine . Calculate the % purity of H2O2. reaction is , H2O2 + 2KI --------} 2KOH + I2

10 ml of H2O2 solution reacts with KI solution to produce 0.5gm of iodine . Calculate the % purity of H2O2.
reaction is , 
H2O2 + 2KI --------} 2KOH + I2

Grade:12

1 Answers

Rituraj Tiwari
askIITians Faculty 1792 Points
3 years ago
Chemical Reaction

H2O2 + 2 I- ---> I2 + 2OH-


In 0.5 g of I2 produced, the moles of I2 will be = 0.5127×2=0.00197 mol

Since 1 mol of I2 is formed by 1 mol of H2O2.
0.00197 mol of ​I2 is formed by 0.00197 mol of H2O2, and the mass of H2O2 reacted = 0.00197 x 34 = 0.067 g

Now, to calculate the percentage purity we must know how much grams of H2O2 is present in the solution, which is missing in the question.


percentage purity = Actual amount of H2O2 reacted (g)/Amount of H2O2 used (g)×100 %

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