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1.The emf of a daniel cell at 298K is E1.Zn/ZnSO4(0.001M)||CuSO4(1.0M)/Cu.when the conc of ZnSO4 is 1M and that of CuSO4 is 0.01Mthe emf changed to E2.What is the relationship between E1 and E22.Given E(Fe3+/Fe)= -0.036V ,E(Fe2+/Fe)= -0.439Vthe value of standard electrode potential for the change Fe3+ + e- giving Fe2+ will be
For E1 = Eocell – (0.0529/2)log(Zn2+/Cu2+) => Eocell – (1.5)(0.0529)........(1)For E2 = Eocell – (0.059)..............(2)Substract the eqns. (1) and (2) we get,E1 – E2 = 0.059*2.5 = > 0.13225 VOLT Fe3+ + 3e- ==> FeandFe2+ + 2e- ===> FeNow reversing the second reaction and addiing with the first, we get the relation as:E1 – E2 = Ecell for Fe3+ + e- giving Fe2+.
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