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1 mole of KCLO3 is thermally decomposed and excess of aluminum is burnt in the gaseous product. How many moles of AIO3 are formed?

1 mole of KCLO3 is thermally decomposed and excess of aluminum is burnt in the gaseous product. How many moles of AIO3 are formed?

Grade:12th pass

1 Answers

Arun
25750 Points
4 years ago
Two reactions occur here are the thermal decomposition of KClO₃ and the subsequent oxidation of Aluminum to form Al₂O₃. 
The two reactions are as follows: 
2 KClO₃ → 2 KCl + 3 O₂ and 4 Al + 3 O₂ → 2 Al₂O₃ 

 When 1 mole KClO₃ is decomposed, 1.5 moles of O₂ is produced ------->
1 mol KClO₃ x ( 3 mol O₂ / 2 mol KClO₃) = 1.5 mol O₂ 

3 moles of oxygen produces 2 moles of aluminum oxide. 
As we have 1.5 moles of oxygen (half of the three needed) we can expect to produce half of the 2 moles or 1 mole aluminum oxide.
1.5 mol O₂ x ( 2 mol Al₂O₃ / 3 mol O₂) = 1 mol Al₂O₃
Thus 1 mol of Al2O3 is produced.

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