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1 mol of MnO4- will oxidise x mol of ferric oxalate in acidic medium, x is---------.Answer: 5/6
MnO4- will oxide to MnO2 thus its v.f would be 5 and Fe3+ would remain fe3+ a dn no. of atoms of Fe3+ is 2 therefore,moles * valence factor = moles * valence factor1 * 5 = x * 3*2 x = 5/6
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