1.520g of hydroxide of metal on ignition gave 0.995g of oxide.The equivalent weight of metal is

Let equivant wt of metal be E now using cobination method and equating the gram equivalents (gmeqs):1.520/E+17 = 0.995/E+80.525E = 4.755E=9.05

One equivalent of the metal reacts with one mole of OH ,i.e, 17 grams.Similarly,one equivalent of the metal reacts with 1/2 moles of oxygen atoms ,i.e, 8grams of oxygen atoms.Let E be the equivalent mass of the metal.And let X be the no. of equivalents of metal hydroxide ignited.Therefore, x[E+17] = 1.520 grams & x[E+8] = 0.995 gramsBy eliminating x , we get E= 9.06 grams..