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0.1 M solution of KI reacts with excess of H2SO4 and KIO3 5I(minus) +IO3(minus)+6H(plus)---> 3I2 +3H2O Which of the following are correct (A) 200 ml of the KI solution react with 0.004 mole KIO3 (B) 100 ml of the KI solution reacts with 0.006 mole of H2 (C) 0.5 litre of the KI solution produced 0.005 mole of I2 (D) Equivalent weight of KIO3 is equal to (Molecular weight/5)

5 years ago

Answers : (1)

Shubham Singh
199 Points
							
D is correct because change in oxidation no. Iodine is 5 form IO3 to I2.
5 years ago
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