Grade 11General Physics
what weight of 70% pure sulphuric acid is require for complete neutralisation of 4 gram of sodium hydroxide?
what weight of 70% pure sulphuric acid is require for complete neutralisation of 4 gram of sodium hydroxide?
1 Answer
Vikas TU
Dear Student,
Lets consider the balance response
H2SO4 + 2NaOH Na2SO4 + 2H2O
From this condition the moles of H2SO4 required here is 0.5 moles
Molar mass of H2SO4 = 2* H + S +4 *O
= 2*1 + 32 + 4*16
= 98g
Gram nuclear mass = Molar mass * moles
= 98 * 0.5
= 49 g
As in the given inquiry, weight of 70% immaculate sulphuric corrosive is require for finish balance of 4 gram of sodium hydroxide
Here 49 g is accessible in 70g of the arrangement
At that point (49*100)/70 = 70g
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Thapar University)
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