what is the bond order and formal charge in case of SO42- and PO43-

bond order is given by (no. of bonds )/(no. of positions)bond order of SO42- is 6/4=1.5bond order of PO43- is 5/4=1.25 formal charge of SO42- = net charge/no. of oxygen atoms=-2/4=-0.5formal charge of PO43- = net charge / no. of oxygen atoms =-3/4

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what is the bond order and formal charge in case of SO₄^2- and PO₄^3-

preet kaur , 6 Years ago

Grade 11

2 Answers

Mayank

bond order is given by (no. of bonds )/(no. of positions)

bond order of SO₄^2-is 6/4=1.5

bond order of PO₄^3- is 5/4=1.25

formal charge of SO₄^2- = net charge/no. of oxygen atoms=-2/4=-0.5

formal charge of PO₄^3- = net charge / no. of oxygen atoms =-3/4

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Last Activity: 6 Years ago

Khimraj

Bond order is equal to Total no of Bonds ( sigma as well as pi) in different resonating structures between any 2 atoms in a molecule/ Total no of resonating structures. In case of PO43- Bond order= 5/4= 1.25. Note: 5 is the total no of sigma and pi between P and O. 4 is the total no of resonating structures.

Last Activity: 6 Years ago