Grade 11Organic Chemistry

Two elements A and B are such that B.E. of A-A ,B-B,A-B are respectively 81 kcal/Mole,64 kcal/Mole, 76 kcal/Mole and electronegativity of B is 2.4 then the electronic configuration of A is , (if xb> xa)

Shilpa Pradhan

9 Years agoGrade 11

1 Answer

Umakant biswal

9 Years ago

@ shilpa
i am giving u the approach to solve the question ,
can u recall the following formula ??
Xa – Xb = 0.208[E(a–b) – {E(a–a) × E(b–b)}^(1/2)]^(1/2)
where ,
Xa - electronegativity of element a
Xb - electronegativity of element b
E(a–b) - bond energy of the molecule (a–b)
E ( a–a) - bond energy of the molecule (a–a)
E (b–b) - bond energy of the molecule (b–b)
if u can then just apply this formula and get the answer .
what u have to do is only to substitute the value and calculate .

HOPE U CAN DO THAT RIGHT NOW , IF NOT THEN LET ME KNOW , I WILL DO FULL CALCULATION FOR YOU .

ALL THE BEST ..