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Two elements A and B are such that B.E. of A-A ,B-B,A-B are respectively 81 kcal/Mole,64 kcal/Mole, 76 kcal/Mole and electronegativity of B is 2.4 then the electronic configuration of A is , (if xb> xa)

Two elements A and B are such that B.E. of A-A ,B-B,A-B are respectively 81 kcal/Mole,64 kcal/Mole, 76 kcal/Mole and electronegativity of B is 2.4 then the electronic configuration of A is , (if xb> xa)

Grade:11

1 Answers

Umakant biswal
5359 Points
5 years ago
@ shilpa 
i am giving u the approach to solve the question ,
can u recall the following formula ?? 
Xa – Xb = 0.208[E(a–b) – {E(a–a) × E(b–b)}^(1/2)]^(1/2)
where , 
Xa - electronegativity of element a 

Xb - electronegativity of element b 
E(a–b) - bond energy of the molecule (a–b) 
E ( a–a) - bond energy of the molecule (a–a) 
E (b–b) - bond energy of the molecule (b–b)
if u can then just apply this formula and get the answer . 
what u have to do is only to substitute the value and calculate . 
HOPE U CAN DO THAT RIGHT NOW , IF NOT THEN LET ME KNOW , I WILL DO FULL CALCULATION FOR YOU . 
ALL THE BEST ..
 

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