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The volume of O2 liberated from 0.96g of H2O2 at STP is

The volume of O2 liberated from 0.96g of H2O2 at STP is

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear student
 
no.of moles of  H2O2 is= 0.96/68=0.014
(68=molecular mass of hydrogen peroxide)
H2O2===>H2 + O2
hence volume of O2 evolved =22.4L*0.014=0.3136L=313.6 mL (22.4L=volume of 1 mole of ideal gas)
 
Regards
Arun (askIITians forum expert)

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