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Grade 11Organic Chemistry

The volume of O2 liberated from 0.96g of H2O2 at STP is

Profile image of Arman Ansari
8 Years agoGrade 11
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1 Answer

Profile image of Arun
8 Years ago
Dear student
 
no.of moles of  H2O2 is= 0.96/68=0.014
(68=molecular mass of hydrogen peroxide)
H2O2===>H2 + O2
hence volume of O2 evolved =22.4L*0.014=0.3136L=313.6 mL (22.4L=volume of 1 mole of ideal gas)
 
Regards
Arun (askIITians forum expert)

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