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Grade: 11
        The volume of O2 liberate from 0.96 g  of H2O2 at STP
11 months ago

Answers : (1)

Arun
15907 Points
							
Dear student
 
no.of moles of  H2O2 is= 0.96/68=0.014
(68=molecular mass of hydrogen peroxide)
H2O2===>H2 + O2
hence volume of O2 evolved =22.4L*0.014=0.3136L=313.6 mL (22.4L=volume of 1 mole of ideal gas)
 
Regards
Arun (askIITians forum expert)
11 months ago
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