Grade 12Organic Chemistry

The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1g of B solid is dissolved in 20g of A,its vapour pressure is reduced to 9 torr if the molecular mass of A is 200amu then the molecular mass of B is

Krisha

8 Years agoGrade 12

3 Answers

Sanam Bedi

8 Years ago

The Actual formula is

(p^o-p^s)/p^o=n/(n+N)

But for our convinience we will neglect ‘n’ here

(p^o-p^s)/p^o=n/(N)

(10-9)10=(1/x)/(1/10)

(1/10)=(10/x)

(1/100)=(1/x)

x=100amu

Therefore, x=100amu

Pooja

7 Years ago

If we will not neglect (n) then answer will be 90 and we must not neglect (n) because it is not mention in question that the amount of A is more than B

Kushagra Madhukar

6 Years ago

Dear student,

Please find the solution to your problem below.

The Actual formula is

(p^o-p^s)/p^o=n/(n+N)

(10 – 9)/10 = (1/x) / [(1/x) + (1/10)]

1/10 = 1/(1 + x/10)

1 + x/10 = 10

x/10 = 9

x = 90amu

Therefore, x = 90amu

Hope it helps.

Thanks and regards,
Kushagra

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The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1g of B solid is dissolved in 20g of A,its vapour pressure is reduced to 9 torr if the molecular mass of A is 200amu then the molecular mass of B is

Krisha

3 Answers

Sanam Bedi

Pooja

Kushagra Madhukar

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